*Wouldn't this imply that all hash functions (other than one-to-one mappings) mu... | Hacker News

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userbinator on Feb 24, 2017 | parent | context | favorite | on: Announcing the first SHA-1 collision

Wouldn't this imply that all hash functions (other than one-to-one mappings) must have collisions?

Yes, they do. Finding them is the hard part.

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