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You need to add:

    (assert (> z 0)) 
    (assert (> x 0)) 
    (assert (> y 0))
or it will give you negative solutions.

I am running this on my machine now. Will report back if it comes up with a solution.



Anything is possible, but I really doubt you'll find those 80 digit numbers. Maybe the sat solver includes some serious number theory though. I doubt it.




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